Вход на сайт

Просмотр новости

Найдите то, что Вас интересует

Why is ##(t_1'-t_2')^2## constant in proof(invariance of intervals)?

Дата публикации: 15-02-2026 23:19:48



Основное содержимое страницы с новостью.

Hello!

When I was proving that coefficient ##a## ##(s'=as)## is equal to ##1##, I noticed that ##(t_1' - t_2')^2## should be constant then the proof works but otherwise it doesn't.

##c^2(t_1'-t_2')^2 - (x_1'-x_2')^2 - (y_1'-y_2')^2 - (z_1'-z_2')^2=a(c^2(t_1-t_2)^2 - (x_1-x_2)^2 - (y_1-y_2)^2 - (z_1-z_2)^2)##

Can anyone explain why should ##(t_1'-t_2')^2## be constant?

Thanks!

Ibix

Science Advisor

2025 Award

What do you mean by "constant"? It's the difference in time coordinates of two events, so of course it doesn't change. But I don't think that's what you mean.

As s=s', s is invariant between IFRs, not its time component quantity you refer.

Схожие новости

#Наименование новостиТональностьИнформативностьДата публикации
1A question about special relativity0521-05-2026
2Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?0504-05-2026
3Why is the Lorentz Force always perpendicular to velocity?0519-06-2026
4Euclidean geometry and gravity0520-02-2026
5Struct parallels between curvature behavior/abstract geometric cycles?0525-03-2026
6Help with problem in MIT open course general relativity0503-04-2026
7Explanation requested for a relativistic scenario wherein two seemingly valid measurement procedures lead to different results for the same observable0518-05-2026
8Singularity Theorems0509-06-2026
9Black hole questions0510-04-2026

Классификация: . Схожих патентов: 0. Схожих новостей: 9. Тональность: 0. Информативность: 5. Источник: www.physicsforums.com.