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TL;DR Summary: Question about molarity and concconcentration
25 cm^(3) of NaOH solution with the molarity of 0.1moldm^(-3) Was measured to a pipette and added to a volumetric flask. Then by adding distilled water to the solution, the solution is diluted until the total volume is 250cm^(3) Find the number of moles of H₂SO required to react with 30.0cm(3) of the solution thus made.
What is your own attempt?
Mayhem said:
What is your own attempt?
0.0003 mol
Mayhem said:
What is your own attempt?
Adheesha said:
TL;DR Summary: Question about molarity and concconcentration
25 cm^(3) of NaOH solution with the molarity of 0.1moldm^(-3) Was measured to a pipette and added to a volumetric flask. Then by adding distilled water to the solution, the solution is diluted until the total volume is 250cm^(3) Find the number of moles of H₂SO required to react with 30.0cm(3) of the solution thus made.
The answer I got is 0.0003 mol.I just wanna know whether it's correct or not cuz I'm not sure about my answer
Assuming you meant H2SO4 - does it react 1:1 with NaOH?
Borek said:
Assuming you meant H2SO4 - does it react 1:1 with NaOH?
NO.It reacts 1:2 with NaOH
Have you accounted for that?
Borek said:
Assuming you meant H2SO4 - does it react 1:1 with NaOH?
NO.It reacts 1:2 with NaO
Borek said:
Have you accounted for that?
I tried to solve the question and the answer I got was 0.0003 moles.can anybody tell me whether it's correct or not?
No, it is not correct, and I already pointed you to a reason why it is wrong.
Write reaction equation, calculate number of moles of NaOH, use the stoichiometry to calculate number of moles of H2SO4.
Borek said:
No, it is not correct, and I already pointed you to a reason why it is wrong.
Write reaction equation, calculate number of moles of NaOH, use the stoichiometry to calculate number of moles of H2SO4.
Ok thank you
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