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Permutations with no long increasing subsequences

Дата публикации: 16-09-2026 16:19:39

Speaker: Christopher HoffmanSpeaker Affiliation: University of WashingtonSpeaker Link: Christopher Hoffman's WebsiteSeptember 23, 2026ESB 2012
CanadaView All EventsAbstract: A uniformly chosen permutation of \(\{1,2,3,\dots,n\}\) has a longest increasing (or decreasing) subsequence of length about \(2n^{1/2}\), and the fluctuations around this are of order \(n^{1/6}\). In this talk, we will consider permutations whose longest increasing subsequence is much shorter than that. In the case where the longest increasing subsequence is of constant order, we show that the appropriately scaled limit of the permutation is given by the eigenvalue process for an ensemble of random matrices. If the longest increasing subsequence has length \(n^a\) for \(a<1/2\), then we think that the limiting object will be the Brownian watermelon.
Permutations with no long increasing subsequencesEvent Topic: 
Probability





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Speaker: 

Christopher Hoffman

Speaker Affiliation: 

University of Washington

Speaker Link: 

Christopher Hoffman's Website

September 23, 2026

ESB 2012

Canada

View All Events

Abstract: 

A uniformly chosen permutation of \(\{1,2,3,\dots,n\}\) has a longest increasing (or decreasing) subsequence of length about \(2n^{1/2}\), and the fluctuations around this are of order \(n^{1/6}\). In this talk, we will consider permutations whose longest increasing subsequence is much shorter than that. In the case where the longest increasing subsequence is of constant order, we show that the appropriately scaled limit of the permutation is given by the eigenvalue process for an ensemble of random matrices. If the longest increasing subsequence has length \(n^a\) for \(a<1/2\), then we think that the limiting object will be the Brownian watermelon.

Event Topic: 

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